Re: Function rule

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"Today I do not have sufficient time to explain the solution in
detail but the answer is y = 6 + 2^(x-1). The rough sketch
of analysis is as below: "

Mohan, I hope this is not how you teach. Sorry no time...here's
the answer!

Maybe instead we can suggest a helpful hint. Maybe we can start by
graphing the (x,y) pairs.

On 9/10/11, Mohan Pawar wrote:
> On 9/10/11, Barb wrote:
>> Could you help me find the function rule for the following x
>> value and Y value respectively:
>> x: 1,2,3,4,5,6
>> Y:7,8,10,14,22,38
>> I see how y changes but seem to be having trouble to relate
>> x to y.
>>
>> Thanks
>
> Today I do not have sufficient time to explain the solution in
> detail but the answer is y = 6 + 2^(x-1). The rough sketch
> of analysis is as below:
>
> Concentrate on Y first. 7 8 10 14
> 22 38 ... See the differences 1 2
> 4 8 16 ... Now relate the
> difference 1, 2, 4, 8, 16 to 2^0, 2^1, 2^3, 2^4 ... *Think
> about how to get 7 as the first term. Conclude y = 6 + 2^(x-1)
> where x = 1, 2, 3, 4 ...
>
> *If your x included 0 then y = 6 + 2^x but that is not the
> case.
>
> Please ignore any typos.
>
>
> Best regards.
>
> Mohan Pawar Website: http://www.mpClasses.com YouTube:
> http://www.youtube.com/user/MathsPhysicsClasses
>
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