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Aug 20, 2005

1.Grab a calculator.. 2.Key in the first three digits of your phone number. (Not area code) 3.Multiply by 80. 4.add 1. 5.Multiply by 250. 6.Add the last 4 digits of your phone number. 7..Add the last 4 digits of your phone number again. 8.Subtract 250. 9.Divide number by 2. 10.Do you recognize the answer?

Please let me know!

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...See More/blockquote>On 8/20/05, Dale wrote: > 1.Grab a calculator.. > 2.Key in the first three digits of your phone number. > (Not area code) > 3.Multiply by 80. > 4.add 1. > 5.Multiply by 250. > 6.Add the last 4 digits of your phone number. > 7..Add the last 4 digits of your phone number again. > 8.Subtract 250. > 9.Divide number by 2. > 10.Do you recognize the answer? > > Please let me know! > Looks the same as doubling your first three digits and moving them over four place values (what multiplying by "80*250" accomplishes i.e. x "20,000") to be able to insert the last four phone number digits (albeit doubled). Of course this is partly hidden by the "mysterious" increase of 250 (1 x 250), which is later removed, and finally removing the doubling factor.

hey ppl this math problem doesnt work for my friend's and my numbers

chanel&ashley

...See More/blockquote>On 8/20/05, Dale wrote: > 1.Grab a calculator.. > 2.Key in the first three digits of your phone number. > (Not area code) > 3.Multiply by 80. > 4.add 1. > 5.Multiply by 250. > 6.Add the last 4 digits of your phone number. > 7..Add the last 4 digits of your phone number again. > 8.Subtract 250. > 9.Divide number by 2. > 10.Do you recognize the answer? > > Please let me know! > Cute algorithm! ...but hardly unbelievable. Where b < 10,000: ((a*80 + 1)250 + 2b - 250)/2 Result: a(10000)+

Awesome

hey this did work 4 me i got my cell #!

thanx diva

angel