Our school is pushing towards a general no-homework policy. Is there anybody out there successfully doing this, or tried it and can offer some feedback? I teach 8th grade pre-algebra.
Standardized learner: Student who's assessment of math learned falls within one standard deviation of class average for a particular class taught by same teacher.
Average homework: Homework that produces a reasonably normal distribution of correctness for a fixed amount of time, which is determined by the teacher. More or less time is not allowed for students.
Teacher grading to student working ratio: The amount of time the teacher needs to grade homework and enter grades. divided by the sum of each each student's time doing homework.
Relative rigor ratio: Level of math curriculum taught in relation to course syllabus.
Student ability level: Level of needed academic preparation to learn at average level in the specified class.
Student engagement index: Percentage of time student actually is attending an assigned learning activity in class.
Assessment integrity index: Percentage of work done by student's independent effort.
As some of my profs have said, "I leave the derivation of the formula as an exercise for you."
So, As you can see, the optimal production process is using continual formative assessment - as has been pointed out.
Note: If you are not sure of the exact formula, remember, you can use the Internet to get it. If you have trouble, most students can show you how for get the answer, even if it's wrong. Anyway, most teachers give completion grades to same grading time.
tag words involved with this question: [ &37; Operator, Matrices, remainder of division, Modulus/Cross-Product ]
tutoring request: Please help me understand the pattern of these results. What aspects of math or bit manipulation is occurring to result in these answers? Please help me visualize the process occurring to achieve these results. These answers are calculated by the Secondlife physics engine consistently.
so 16 mod 2 = 0 16 mod 8 = 0 17 mod 8 = 1 7...See More Mr/Ms Modulo Dec 30, 2014 That was a fantastically educational answer! and yes it took this long for me to get back into it considering the Christmas insanity! Thank you so much for a very helpful response! This is going to be very useful to me in my work! thank you! *happy hugs!* Good tutorial!
so 16 mod 2 = 0 16 mod 8 = 0 17 mod 8 = 1 75 mod 50 = 25 75 mod 25 = 0 2 mod 490834752349 = 2
thank you for helping me understand! *^-^*
On 12/30/14, Modulo wrote: > The operator you are designating &37; is usually (in the US > anyway) called mod. So where you write 10 &37; 2 I would > normally write 10 mod 2. > > Basically what the value of "a mod b" is the remainder when > a is divided by b. > > Looking at some of your examples, the last 9 of them had a > value of 4 because if you divide 4 by a number that is > bigger than 4 you will always get a remainder of 4 > > You also had 2 mod 100 as 2, which makes sense since if you > divide 2 by 100 you have a remainder of 2. > > 18 mod 4 would be 2 (4 goes into 18 4 times (which we do > not care about) with a remainder of 2, which is the value > of the expression. > > The tricky ones are the negatives, but it still holds > together (as math should). Let's look at 4 mod -3. How > many times does 03 divide into 4? -1. And what is the > remainder? 1. > > 4 mod -2 : -2 goes into 4 -2 times with a remainder of 0 so > 4 mod -2 = 0 > > I hope this helps. This is one of those concepts that is > really simple once it clicks. Hopefully now it will click. > Feel free to ask follow-ups. > > On 12/29/14, ChristineBunny wrote: >> High-school education, >> Procedural-programing education, >> Fair bitwise-operation education, >> >> tag words involved with this question: >> [ &37; Operator, Matrices, remainder of division, >> Modulus/Cross-Product ] >> >> tutoring request: >> Please help me understand the pattern of these results. >> What aspects of math or bit manipulation is occurring to >> result in these answers? Please help me visualize the >> process occurring to achieve these results. >> These answers are calculated by the Secondlife physics >> engine consistently. >> >> 2 &37; 100=2 >> 3 &37; 100=3 >> 100 &37; 2=0 >> 100 &37; 3=1 >> 4 &37; -4=0 >> 4 &37; -3=1 >> 4 &37; -2=0 >> 4 &37; -1=0 >> 4 &37; 1=0 >> 4 &37; 2=0 >> 4 &37; 3=1 >> 4 &37; 4=0 >> 4 &37; 5=4 >> 4 &37; 6=4 >> 4 &37; 7=4 >> 4 &37; 8=4 >> 4 &37; 9=4 >> 4 &37; 10=4 >> 4 &37; 11=4 >> 4 &37; 12=4 >> 4 &37; 16=4
On 1/12/15, ChristineBunny wrote: > > > Mr/Ms Modulo Dec 30, 2014 > That was a fantastically educational answer! and yes it took > this long for me to get back into it considering the Christmas > insanity! Thank you so much for a very helpful response! This is > going to be very useful to me in my work! thank you! *happy > hugs!* Good tutorial! > > so > 16 mod 2 = 0 > 16 mod 8 = 0 > 17 mod 8 = 1 > 75 mod 50 = 25 > 75 mod 25 = 0 > 2 mod 490834752349 = 2 > > thank you for helping me understand! *^-^* > > > > On 12/30/14, Modulo wrote: >> The operator you are designating &37; is usually (in the US >> anyway) called mod. So where you write 10 &37; 2 I would >> normally write 10 mod 2. >> >> Basically what the value of "a mod b" is the remainder when >> a is divided by b. >> >> Looking at some of your examples, the last 9 of them had a >> value of 4 because if you divide 4 by a number that is >> bigger than 4 you will always get a remainder of 4 >> >> You also had 2 mod 100 as 2, which makes sense since if you >> divide 2 by 100 you have a remainder of 2. >> >> 18 mod 4 would be 2 (4 goes into 18 4 times (which we do >> not care about) with a remainder of 2, which is the value >> of the expression. >> >> The tricky ones are the negatives, but it still holds >> together (as math should). Let's look at 4 mod -3. How >> many times does 03 divide into 4? -1. And what is the >> remainder? 1. >> >> 4 mod -2 : -2 goes into 4 -2 times with a remainder of 0 so >> 4 mod -2 = 0 >> >> I hope this helps. This is one of those concepts that is >> really simple once it clicks. Hopefully now it will click. >> Feel free to ask follow-ups. >> >> On 12/29/14, ChristineBunny wrote: >>> High-school education, >>> Procedural-programing education, >>> Fair bitwise-operation education, >>> >>> tag words involved with this question: >>> [ &37; Operator, Matrices, remainder of division, >>> Modulus/Cross-Product ] >>> >>> tutoring request: >>> Please help me understand the pattern of these results. >>> What aspects of math or bit manipulation is occurring to >>> result in these answers? Please help me visualize the >>> process occurring to achieve these results. >>> These answers are calculated by the Secondlife physics >>> engine consistently. >>> >>> 2 &37; 100=2 >>> 3 &37; 100=3 >>> 100 &37; 2=0 >>> 100 &37; 3=1 >>> 4 &37; -4=0 >>> 4 &37; -3=1 >>> 4 &37; -2=0 >>> 4 &37; -1=0 >>> 4 &37; 1=0 >>> 4 &37; 2=0 >>> 4 &37; 3=1 >>> 4 &37; 4=0 >>> 4 &37; 5=4 >>> 4 &37; 6=4 >>> 4 &37; 7=4 >>> 4 &37; 8=4 >>> 4 &37; 9=4 >>> 4 &37; 10=4 >>> 4 &37; 11=4 >>> 4 &37; 12=4 >>> 4 &37; 16=4
Greetings I am a retired teacher of 33 yrs with an additional 3 yrs of consulting work to various school districts across the US. I am looking to mentor teachers. I have experience teaching grades 4-12. I am open to share a wealth of ideas, strategies ,and techniques that would enhance daily learning in the classroom. Thank you.
Greetings Everyone! My name is Greg Mason and I am new to the post! I'm honored to be here and I look forward to networking with you all and exchanging ideas on math problems and solutions.
First, some basic vocabulary:
Standardized learner: Student who's assessment of math learned falls within one standard deviation of class average for a particular class taught by same teacher.
Average homework: Homework that produces a reasonably normal distribution of corr...See More