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I don't believe I've ever started a thread here, but since I was here a few moments ago replying to someone else, I thought I'd toss out a neat trig. result that could easily be worked into a trig. or precalculus class as an application of the sine angle subtraction formula.

Problem. Show that the following are all equal to each other:

tan(99 degrees), tan(999 degrees), tan(9999 degrees), tan(99999 degrees), etc.

Hint/Proof-Outline. It suffices to show that each of these is equal to tan(99 degrees). Now observe that the equation "tan(999...9 degrees) = tan(99 degrees)" is equivalent to an equation of the form AB - CD = 0, where A,B,C,D are the sine or cosine of 99 degrees or 999...9 degrees. Use the sine angle subtraction formula to compress this and then note that the angle you're taking the sine of is an integer multiple of 180 degrees. Finally, work backwards from this to get a proof of what we wanted to prove.
math passerby On 7/31/12, math passerby wrote: > Problem. Show that the following are all equal to each > other: > > tan(99 degrees), > tan(999 degrees), > tan(9999 degrees), > tan(99999 degrees), etc.

There is an easier way to show this than the way I suggested earlier.

999 = 900 + 99 = 5(180) + 99,

9999 = 9000 + ...See More
Jul 31, 2012


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